LUA正则表达式不完全指南

2014-02-23 15:14| 查看: 8435 |作者: 小雪

string.gmatch(s,pattern)
多次匹配并且返回所有符合条件的项目
s代表目标字符串
pattern代表条件

s = "1number123xyz"
for x in string.gmatch(s,"%d+") do --匹配数字，一次或多次
print(x)
end
--> x = 1, x = 123

s = "1number123xyz"
for x in string.gmatch(s,"%d-") do --匹配数字，0次或多次，最短匹配
print(x)
end
-->完成匹配，返回空白

s = "1number123xyz"
for x in string.gmatch(s,"%d*") do --匹配数字，0次或多次，最长匹配
print(x)
end
-->1 123 --中间为空白

t = {}s = "hello=123，       lua=456"
for k,v in string.gmatch(s,"(%w+)=(%w+)") do --匹配等号两边的数字与字母一次或多次，并且分别返回括号内的两个值
t[k]=v
print(k,v)
end
--> hello    123
   lua    456
--> t= {["hello"]="123",["lua"]="456"}

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LUA正则表达式不完全指南

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