LUA正则表达式不完全指南
2014-02-23 15:14| 查看: 8423 |作者: 小雪
常用string操作: 参考资料:http://www.lua.org/manual/5.1/manual.html string.find(s,pattern[,init[,plain]]) 匹配第一个符合条件的项目并且起始位置与终止位置，如果没找到则返回nil s代表目标字符串 pattern代表你要匹配的规则，见上面正则表格 init代表开始匹配的位置，默认为1，可以是负数，可不填 plain必须填写init，布尔值，如果为true时，则执行匹配任何匹配规则不生效，只是简单的字面匹配
s = "%d+002929aciwe%a+cqoe01230" s = "%d+002929aciwe%a+cqoe01230" s = "%d+002929aciwe%a+cqoe01230" s = "%d+002929aciwe%a+cqoe01230" |
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